Call MethodInfo.Invoke with an out parameter

admin — Fri, 21 Aug 2009 19:19:21 +0000

Taken from http://www.galcho.com/Blog/P…

Here is how to call a method with an out parameter using MethodInfo.Invoke, in this case the out parameter is the last one (int).

int parNum = 0;
string parText = “99″;
object[] methodParms = new object[] { parText, parNum };

MethodInfo methInfo = parNum.GetType().GetMethod(“TryParse”, new Type[] { typeof(string), typeof(int).MakeByRefType() });
methInfo.Invoke(null, methodParms);
parNum = (int)methodParms[1];
Console.WriteLine(“Parsed number:{0}”, parNum);

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Generic Method Overloading in C#

admin — Tue, 17 Feb 2009 12:54:46 +0000

Say you have an outer method:
public OuterMethod(object x) { InnerMethod(x); }
and an inner method with these overloads
public InnerMethod(object x) { //Generic Actions } public InnerMethod(Person x) { //Person Specific Actions } public InnerMethod(Dog x) { // Dog Specific Actions }
How do you make it so that when the outer method calls the inner method it completes the specific actions as well as the generic ones that allows you to add an overload without editing any other function (useful when working on a team). Well here is the answer…

System.Reflections allows you to search for the relevant method by descibing what it looks like
using System.Reflection; ... public InnerMethod(Object x) { MethodInfo methodInfo = entity.GetType().GetMethod( "InnerMethod", new Type[] { x.GetType() }); if(methodInfo != null) { methodInfo.invoke(this,Invoke(null, new object[] { x }) ; } // Generic Actions }

Now every time you add or remove a method, you only have to add or remove it in one place.

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Stephen Lacy » System.Reflection

Call MethodInfo.Invoke with an out parameter

Generic Method Overloading in C#